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11 August, 07:27

What is the vertex of the quadratic functio f (x) = (x-6) (x+2) ?

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  1. 11 August, 11:15
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    The vertex would be (2, - 16)

    Step-by-step explanation:

    f (x) = x²+2x-6x-12

    f (x) = x²-4x-12

    f' (x) = 2x-4

    2x-4=0

    2x=4

    x=4/2

    x = 2

    f (2) = (2) ²-4 (2) - 12

    f (2) = -16

    = (2,-16)
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