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27 December, 19:49

Solve the equation on the interval 0 ≤ θ < 2π.

2 cos ^2 θ - 3 cos θ + 1 = 0

Would really appreciate answer for this.

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Answers (1)
  1. 27 December, 20:52
    0
    {0, π/3, 5π/3}

    Step-by-step explanation:

    Let x = cos θ. Then:

    2x² - 3x + 1 = 0

    x = (3 ± 1) / 4

    x1 = 1, x2 = 1/2

    If cos θ = 1, then θ = 0

    If cos θ = 1/2, then θ = π/3 or 5π/3
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