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9 October, 16:48

If the length I of a rectangle is 3 more than twice the width w. The area is 90. Find the width

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  1. 9 October, 18:36
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    w = 6

    Step-by-step explanation:

    Givens

    Area = 90

    Let the width = w

    Let the length = 2w + 3

    Formula

    Area = L * W

    Solution

    Area = (2w + 3) * w

    Area = (2w + 3) * w = 90 Remove the brackets.

    Area = 2w^2 + 3w = 90 Subtract 90 from both sides.

    2w^2 + 3w - 90 = 0

    This will factor into

    (w - 6) (2w + 15) = 0

    Only w - 6 will = a zero that makes sense when speaking of an area

    w - 6 = 0

    w = 6

    L = 2*w + 3

    L = 2*6 + 3

    L = 15

    The width is 6
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