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Trinity Abbott
26 November, 16:45
If (x) = 2e^x-1 + 3, what is f^-1 (x)
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Jayvion Bird
26 November, 17:43
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f^-1 (x) = 1+ln ((x-3) / 2)
Step-by-step explanation:
hello:
let f (x) = y so : y = 2e^ (x-1) + 3
calculate x : e^ (x-1) = (y-3) / 2
for : y-3 > 0 : x-1 = ln ((y-3) / 2) so : x = 1+ln ((y-3) / 2)
If (x) = 2e^ (x-1) + 3, what is f^-1 (x) = 1+ln ((x-3) / 2)
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