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2 May, 04:07

Find the value of k, for which one root of quadratic equation kx²-14x+8=0 is 2

+5
Answers (2)
  1. 2 May, 06:39
    0
    k = 5

    since x = 2 is a root then f (2) = 0

    substitute x = 2 into the equation

    4k - 28 + 8 = 0

    4k - 20 = 0 (add 20 to both sides)

    4k = 20 (divide both sides by 4)

    k = 5
  2. 2 May, 06:54
    0
    If one root is 2 then

    k (2) ^2 - 14 (2) + 8 = 0

    4k - 28 + 8 = 0

    4k = 28 - 8

    4k = 20

    k = 5 (answer)
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