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Mathematics
Gilmore
6 May, 04:46
Completely factored form of xy^3 - x^3y?
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Abram Coffey
6 May, 05:38
0
xy (y - x) (y + x)
Step-by-step explanation:
take out a common factor xy from both terms
= xy (y² - x²)
y² - x² is a difference of squares and factors in general as (y - x) (y + x)
Hence
xy³ - x³y = xy (x - y) (x + y)
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