Consider j (x) = 2x - 5

Find j^-1 (x) algebraically.

j^-1 (x) = 1/2 (x+5)

Step-by-step explanation:

1. Replace j (x) with y to make it easier

y = 2x - 5

2. Switch the places of x and y

x = 2y - 5

3. Solve for y

x + 5 = 2y

y = 1/2 (x+5)

4. Replace y with j^-1 (x)

j^-1 (x) = 1/2 (x+5)