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Mathematics
Kelly Michael
8 December, 23:49
Consider j (x) = 2x - 5
Find j^-1 (x) algebraically.
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9 December, 03:27
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j^-1 (x) = 1/2 (x+5)
Step-by-step explanation:
1. Replace j (x) with y to make it easier
y = 2x - 5
2. Switch the places of x and y
x = 2y - 5
3. Solve for y
x + 5 = 2y
y = 1/2 (x+5)
4. Replace y with j^-1 (x)
j^-1 (x) = 1/2 (x+5)
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