A fair dice is rolled 6 times. What is the probability of having no 2 and no 3 among the rolls? Round your answer to three decimal places.

64/729

or 0.088 to 3 decimal places.

Step-by-step explanation:

The probability of no 2 and no 3 on one throw of the dices = 4/6 = 2/3.

For 6 rolls we multiply this 6 times because each throw is independent.

The answer is (2/3) ^6

= 64/729

or 0.088 to 3 decimal places.