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Mathematics
Michael Lozano
6 February, 14:36
What is the factor of 16^2-81
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Alfie
6 February, 15:18
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This is the diffiarence of two perfect squares. this should be memorised, but if not here it is
a^2-b^2 = (a-b) (a+b)
so 16^2-81=16^2-9^2
so the answer is (16-9) (16+9)
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