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2 December, 18:23

what are the possible values of x in 8x^2+4=-1 a. 2+-iroot/3 b. - 1+-i/6 c.-1+-i/4 d. 1+-i/4 e. 1+-i root 2/4

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  1. 2 December, 22:02
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    x = ± i sqrt (5/8)

    Step-by-step explanation:

    8x^2+4=-1

    Subtract 4 from each side

    8x^2+4-4=-1-4

    8x^2 = - 5

    Divide by 8

    8/8x^2=-5/8

    x^2 = - 5/8

    Take the square root of each side

    sqrt (x^2) = ±sqrt (-5/8)

    x = ±sqrt (-5/8)

    x = ±sqrt (5/8) sqrt (-1)

    x = ± i sqrt (5/8)
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