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30 December, 08:21

What is the product (y+3) (y^2-3y+9)

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  1. 30 December, 11:48
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    y^3 + 3^3

    Step-by-step explanation:

    1) Multiply each term of (y^2-3y+9) by y: y^3 - 3y^2 + 9y

    2) Multiply each term of (y^2-3y+9) by 3: 3y^2 - 9y + 27

    3) Add all of these terms together: y^3 + 27 = y^3 + 3^3

    Note: this is an example of 'special products and factoring.'
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