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25 August, 18:14

At time t, there are 216t + 18 bacteria of type A and 362t + 8 bacteria of type B organisms in a sample. When will the number of each type of bacteria be equal?

Answers voices are:

A) t=38

B) t=-38

C) t=6

D) t=9/4

+5
Answers (1)
  1. 25 August, 18:43
    0
    We must set the two expressions to be equal:

    216t + 18 = 362t + 8

    Subtract 216t from both sides:

    18 = 146t + 8

    Subtract 8 from both sides:

    10=146t

    Divide both sides by 146:

    t = 10/146 = 5/73
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