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26 February, 04:34

Which function has real zeros at x = 3 and x = 7?

Of (x) = x2 + 4x - 21

O f (x) = x2 - 4x - 21

Of (x) = x2 - 10x + 21

O f (x) = x2 - 10x - 21

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Answers (1)
  1. 26 February, 05:22
    0
    The answer is X2-10X+21

    Explanation: If u put the equation in the graphing calculator 3 and 7 both equal zero meaning they are the x's of the situation.
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