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19 March, 07:45

The function P (x) = x3-2x2 is dilated by the function I (x) = P (4x).

Which function rule represents I (x) ?

I (x) = 64x3-2x2

I (x) = 4x3-2x2

I (x) = 64x3-32x2

I (x) = 4x3-8x2

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  1. 19 March, 08:35
    0
    I (x) = 64x³-32x²

    Step-by-step explanation:

    We are given the function P (x) = x³-2x².

    I (x) is given P (4x).

    This means to get I (x), we replace x in the function P (x) to be 4x.

    Therefore:

    I (x) = P (4x) = (4x) ³-2 (4x) ²

    I (x) = P (4x) = 64x³ - 2 (16x²)

    I (x) = 64x³ - 32x²

    Therefore the function rule that represents I (x) is 64x³ - 32x².
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