A number cube has the numbers 1, 2, 5, 5, 6, and 6 on its faces. Match the probability with the outcome. 1. P (5 ∪ 6) 2. P (2 ∪ 5 ∪ 6) 3. P (1 ∪ 2) 4. 0 P (4)

1. P (5 U 6) = 2/3

2. P (2 U 5 U 6) = 5/6

3. P (1 U 2) = 1/3

4. P (4) = 0

Step-by-step explanation:

As the number cube has 6 sides,

So,

Total outcomes = {1,2,5,5,6,6}

n (S) = 6

Now,

1. P (5U6) = P (5) + P (6)

P (5) = 2/6=1/3

P (6) = 2/6=1/3

P (5U6) = 1/3 + 1/3 = 2/3

2. P (2 U 5 U 6) = P (2) + P (5) + P (6)

P (2) = 1/6

P (5) = 2/6

P (6) = 2/6

P (2 U 5 U 6) = 1/6 + 2/6 + 2/6

= 5/6

3. P (1 U 2) = P (1) + P (2)

P (1) = 1/6

P (2) = 1/6

P (1 U 2) = 1/6 + 1/6

= 2/6 = 1/3

4. P (4) = 0

As 4 is not in the outcomes, it's probability will be zero ...