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13 December, 16:34

Enter an exponential growth function to model each situation. Then find the value of the function after the given amount of time. Use t to represent the time in yearsRound the value for the population after the given amount of time to the nearest hundredth. The population of a small town is 1.700 and is increasing at a rate of 2% per year; 10 years.

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  1. 13 December, 19:30
    0
    Exponential growth function: P = 1700*e^ (0.02*t)

    After 10 years, the amount of population will be 2076

    Step-by-step explanation:

    Population growth is modeled by the following equation:

    P = P0*e^ (r*t)

    where P is final population, P0 is initial population, r is rate of growth (as decimal) and t is time (in years)

    Replacing with P0 = 1700, r = 0.02 and t = 10, we get:

    P = 1700*e^ (0.02*10) = 2076.38
  2. 13 December, 20:14
    0
    Exponencial function: P = 1700 * (1 + 0.02) ^t

    For t = 10 years: P = 2072.29

    Step-by-step explanation:

    The exponencial function is given by:

    P = Po * (1 + r) ^t

    Where P is the final value, Po is the inicial value, r is the rate and t is the time.

    In this case, we have that Po = 1700, r = 2% = 0.02 and t = 10 years.

    So using these values in the equation, we can find the value of P:

    P = 1700 * (1 + 0.02) ^10

    P = 1700 * (1.02) ^10

    P = 2072.29

    So the population after 10 years will be 2072.29
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