Which of the following are the solutions of the equation 2x^2+2x=4-x

(A) x=4 and x=1

(B) x=4 and x = - 1/2

(C) x = 3+√35/4 and x=3-√35/4

(D) x=-3+√41/4 and - 3-√41/4

(E) - 3+i√23/2 and - 3-i√23/2

2x² + 2x = 4 - x

+ x + x

2x² + 3x = 4

2x² + 3x - 4 = 0

x = - (3) + / - √ ((3) ² - 4 (2) (-4))

2 (2)

x = - 3 + / - √ (9 + 32)

4

x = - 3 + / - √ (41)

4

x = - 3 + / - 6.4

4

x = - 0.75 + 1.6

x = - 0.75 + 1.6 x = - 0.75 - 1.6

x = 0.85 x = - 16.75

The answer is equal to D. x = - 0.75 + √ (41) / 4 and x = - 0.75 - √ (41) / 4.