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25 March, 13:30

202 tickets are sold. a child costs $6 and an adult ticket costs $10. How may tickets of each were sold if the receipts totaled $1708?

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  1. 25 March, 15:03
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    The number of child tickets = 78 and the number of adult tickets = 124

    Step-by-step explanation:

    Let the number of child ticket is x and the adult ticket is y

    ∴ x + y = 202 ⇒ (1)

    ∵ The cost of child ticket is $6 and adult ticket is $10

    ∴ 6x + 10 y = 1708 ⇒ (2)

    Solve the system of equations (1) and (2)

    Multiply (1) by - 6 to eliminate x

    ∴ - 6x + - 6y = - 1212 ⇒ (3)

    Add (2) and (3)

    ∴ 4y = 496

    ∴ y = 124

    Substitute the value of y in (1)

    ∴ x + 124 = 202 ⇒ x = 202 - 124 = 78

    ∴ The number of child tickets = 78 and the number of adult tickets = 124
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