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14 November, 18:37

Select the correct answer. What are the values of x in this equation? 'x^ (2/5) + x^ (1/5) + 1 = 3' A. 32, - 1 B. 32, 1 C. - 32, 1 D. - 32, - 1

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  1. 14 November, 21:09
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    x^ (2/5) + x^ (1/5) + 1 = 3

    subtract 3 from each side

    x^ (2/5) + x^ (1/5) - 2=0

    let m = x^1/5

    m^2 + m - 2 = 0

    (m - 1) (m + 2) = 0

    using the zero product property

    m=1 m=-2

    replace m = x^1/5

    x^1/5 = 1 and x^1/5 = - 2

    take everything to the 5th powr

    x^ 1/5 ^ 5 = 1^5 and x^ 1/5 ^ 5 = - 2 ^ 5

    x = 1 and x = - 32

    Choice C

    C. - 32, 1
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