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19 July, 02:21

One number is eight less than the second number. Twice the first is 9 more than 3 times the second. Find the numbers

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  1. 19 July, 03:43
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    -49/3 and - 25/3

    Step-by-step explanation:

    Let the numbers be represented by f and s (first and second). Then f = s - 8. Also, 2f = 3s + 9. Solve this system for f and s:

    Substituting s - 8 for f in the 2nd equation, above, yields

    2 (s - 8) = 3s + 9, or 2s - 16 = 3s + 9. Then 3s = - 25, and s = - 25/3. The first number is then f = s - 8, or f = - 25/3 - 8, or f = - 49/3.
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