The sum of three consecutive integers is 312

Let x be for unknown number. Let x be first number. X+1 To be second number. x+2be third number. X + (x+1) + (x+2) = 312. Simplify to get 3x+3=312. Subtract 3 from both sides 3x-3=312-3. Once you subtract get 3x=109. then divide 3 both sides. 3x/3=309/3. To get x = 103. Now once you have that First number 103. Second number 103+1=104. And third number 103+2=105. To check add them 103+104+105=312