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17 January, 02:42

Use natural logarithms to solve the equation 5e^3x+7=21

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  1. 17 January, 03:04
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    5e^ (3x+7) = 21

    e^ (3x+7) = 4.2

    (3x+7) lne=ln4.2

    lne=1

    3x+7=1.435

    3x = - 5.565

    x = - 1.855
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