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Rohan Haas
6 June, 08:11
What is the solution set of 8x^2 - 2x - 1 = 0
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Marina Wood
6 June, 11:53
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Step-by-step explanation:
4x^2 - 8x > = 0
Factor left side
4x (x - 2) >=0
Then case I) 4x <=0 and x - 2 < = 0
so x < = 0 and x < = 2
So x < = 0
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