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6 June, 08:11

What is the solution set of 8x^2 - 2x - 1 = 0

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  1. 6 June, 11:53
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    Step-by-step explanation:

    4x^2 - 8x > = 0

    Factor left side

    4x (x - 2) >=0

    Then case I) 4x <=0 and x - 2 < = 0

    so x < = 0 and x < = 2

    So x < = 0
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