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6 June, 19:47

The length of a rectangular sign is 3 times its width. If the sign's perimeter is 32 inches, what is the sign's area?

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  1. 6 June, 21:14
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    Answer:48 square inche

    Step-by-step explanation:

    Length (L) = 3 x width (W)

    L=3xW

    Perimeter (p) = 2L+2W=32

    2L+2W=32

    substitute L=3xW in 2L+2W=32

    2 (3xW) + 2W=32

    6W+2W=32

    8W=32

    Divide both sides by 8

    8W/8=32/8

    W=4 width=4

    Substitute w=4 in L=3xW

    L=3x4

    L=12 Length=12

    Area=length x width

    Area=12 x 4

    Area=48
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