Given: F (x) = 2x - 1; G (x) = 3x + 2; H (x) = x2

Find G[H (1)).

5

Step-by-step explanation:

The question ask for G[H (1) ] so we have to find the H (1) first and it doesn't ask for anything about the F (x) so we don't have to worry about it. I dont know if H (x) = x*2 or x^2 but i'll consider it as x^2.

H (1) = (1) ^2 Plug in 1 for x

H (1) = 1

since we find H (1) = 1 we just put it as G (1) because its same as G[H (1) ]

G (1) = 3x + 2

G (1) = 3 (1) + 2 = 5

G (1) = G[H (1) ] = 5