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16 May, 13:33

A cone frustum is inscribed in a sphere of radius 13. If one of the bases of the frustum is a great circle of the sphere, and the other base has radius 12, what is:

The height of the frustum?

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Answers (1)
  1. 16 May, 16:59
    0
    5

    Step-by-step explanation:

    According to the question, A cone frustum is inscribed in a sphere of radius 13. If one of the bases of the frustum is a great circle of the sphere, and the other base has radius 12. We are now asked to find the height of the frustum.

    ---The height of this frustum is equal to the distance of its smaller base from the center of the sphere.

    Therefore, it is assigned the pattern

    H = √ (r1² - r2²

    Where r1 is the radius of the sphere

    And r2 is the radius of the other base of the frustum

    H is the height that we are looking for

    H = √ (13² - 12²)

    = √ (169 - 144)

    = √ 25

    H = 5
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