Ask Question
18 August, 19:44

If m^2 + n^2 = 18 and mn=7, what is (m-n) ^2

+2
Answers (2)
  1. 18 August, 21:11
    0
    (m - n) ^2 = 4

    Step-by-step explanation:

    (m - n) ^2 = m^2 - 2mn + n^2 when (m-n) ^2 is expanded using foil.

    But m^2 + n^2 = 18 Given

    mn = 7 Given

    (m - n) ^2 = m^2 + n^2 - 2 mn Substitute in the given values

    (m - n) ^2 = 18 - 2*7 Reduce

    (m - n) ^2 = 18 - 14 Combine

    (m - n) ^2 = 4
  2. 18 August, 21:18
    0
    (m-n) ^2 = m^2 - 2mn + n^2

    (m-n) ^2 = m^2 + n^2 - 2mn

    Substitute m^2 + n^2 = 18 and mn=7

    (m-n) ^2 = 18 - 2 (7)

    (m-n) ^2 = 18 - 14

    (m-n) ^2 = 4
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If m^2 + n^2 = 18 and mn=7, what is (m-n) ^2 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers