If f (x) = 9x-8 and g (x) = x^3, what is (g o f) (1) ?

(f∘g) (3) = f (g (3))

Find g (3) by substituting x=3 in g (x)

g (x) = x²-1

g (3) = 3²-1

g (3) = 9-1

g (3) = 8

f*g (3) = f (g (3)) = f (8)

find f (8) by substituting x=8 in f (x):

f (x) = 2x+3

f (8) = 2 (8) + 3

f (8) = 16+3

f (8) = 19

So f∘g (3) = 19

Sorry I am wrong