Ask Question
29 June, 11:34

Consider the system of linear equations. 5 x + 10 y = 15. 10 x + 3 y = 13 To use the linear combination method and addition to eliminate the x-terms, by which number should the first equation be multiplied? - 2 Negative one-half One-half 2

+4
Answers (2)
  1. 29 June, 13:18
    0
    Solve the following system:

    {5 x + 10 y = 15 | (equation 1)

    10 x + 3 y = 13 | (equation 2)

    Swap equation 1 with equation 2:

    {10 x + 3 y = 13 | (equation 1)

    5 x + 10 y = 15 | (equation 2)

    Subtract 1/2 * (equation 1) from equation 2:

    {10 x + 3 y = 13 | (equation 1)

    0 x + (17 y) / 2 = 17/2 | (equation 2)

    Multiply equation 2 by 2/17:

    {10 x + 3 y = 13 | (equation 1)

    0 x+y = 1 | (equation 2)

    Subtract 3 * (equation 2) from equation 1:

    {10 x+0 y = 10 | (equation 1)

    0 x+y = 1 | (equation 2)

    Divide equation 1 by 10:

    {x+0 y = 1 | (equation 1)

    0 x+y = 1 | (equation 2)

    Collect results:

    Answer: x = 1, y = 1
  2. 29 June, 15:29
    0
    Solve the following system:

    5 x + 10 y = 15 | (equation 1)

    10 x + 3 y = 13 | (equation 2)

    Swap equation 1 with equation 2:

    {10 x + 3 y = 13 | (equation 1)

    5 x + 10 y = 15 | (equation 2)

    Subtract 1/2 * (equation 1) from equation 2:

    {10 x + 3 y = 13 | (equation 1)

    0 x + (17 y) / 2 = 17/2 | (equation 2)

    Multiply equation 2 by 2/17:

    {10 x + 3 y = 13 | (equation 1)

    0 x+y = 1 | (equation 2)

    Subtract 3 * (equation 2) from equation 1:

    {10 x+0 y = 10 | (equation 1)

    0 x+y = 1 | (equation 2)

    Divide equation 1 by 10:

    {x+0 y = 1 | (equation 1)

    0 x+y = 1 | (equation 2) {

    Collect results:

    Answer: x = 1/2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Consider the system of linear equations. 5 x + 10 y = 15. 10 x + 3 y = 13 To use the linear combination method and addition to eliminate ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers