If (f + g) (x) = 3x2 + 2x - 1 and g (x) = 2x - 2, what is f (x) ?

A.

3x2 + 1

B.

3x2 - 1

C.

3x2 + 4

D.

3x2 - 4

E.

x2 - 2

the A is right

Step-by-step explanation:

We have (f+g) (x) = f (x) + g (x)

So f (x) + g (x) = 3x^2 + 2x - 1 and we know g (x) = 2x - 2

or f (x) + 2x-2 = 3x^2 + 2x - 1

f (x) = 3x^2 + 2x - 1 - (2x - 2)

f (x) = 3x^2 + 2x - 1 - 2x + 2 /

finally

f (x) = 3x^2 + 1, and the A is right.

Have a good day