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20 October, 06:27

What are the roots of the equation? x2 (6x-11) (7x-8) = 0

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  1. 20 October, 09:44
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    x=0 or x=8/7 or x=11/6

    Step-by-step explanation:

    x2 (6x-11) (7x-8) = 0

    42x4-125x3+88x2=0

    x2 (7x-8) (6x-11) = 0

    x2=0 or 7x-8=0 or 6x-11=0

    x=0 or x=8/7 or x=11/6
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