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20 November, 19:14

What is the recursive formula for 3,7,11,15, ...

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  1. 20 November, 20:20
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    Arithmetic sequence: a_n=a_1 + (n-1) d where: d = common difference between terms; n = term; a_1 = first term of sequence a_n = 3 + (n-1) 4 = 3 + (4n-4) = 4n-1 Therefore, a_50 = 4 (50) - 1 = 200 - 1 = 199
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