a club has 10 members.

If the club is sending 3 members to a convention, how many different groups of 3 members are possible?

That is the combination of 10 over 3, which is calculated as the quotient of factorials:

n!/k! (n-k) !

where n = 10 and k = 3:

= 10!/3! (10 - 3) !

= 10!/3!*7!

= (10*9*8) / (3*2*1)

= 720/6

= 120

therefore there a re 120 possible different groups

Okay so you have 10 members. So you would go 10 divided by 3 that is equal to 9 with one left over.