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7 December, 03:29

Find the zeros of each function.

f (x) = x^2 + 5x - 6

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Answers (2)
  1. 7 December, 04:44
    0
    zeros of function f (x) = x^2 + 5x - 6 is 1 and - 6

    Step-by-step explanation:

    Let f (x) = x^2 + 5x - 6

    To find the Zeros

    consider two numbers - 1 and - 6

    Let - 1 * 6 = 6

    -1 + 6 = 5

    f (x) can be written as,

    f (x) = x^2 + 5x - 6

    f (x) = x^2 - x + 6x - 6

    f (x) = x (x - 1) + 6 (x - 1)

    f (x) = (x - 1) (x + 6)

    Therefore zeros of f (x) = 1 and - 6
  2. 7 December, 06:41
    0
    x=1 x=-6

    Step-by-step explanation:

    f (x) = x^2 + 5x - 6

    What two number multiply together to give us - 6 and add to give us 5

    -1 * 6 = - 6

    -1 + 6 = 5

    (x-1) (x+6) = 0

    Using the zero product property

    x-1 = 0 x+6 = 0

    x-1+1=0+1 x+6-6=0-6

    x=1 x=-6
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