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24 November, 23:22

Evaluate the discriminant of each equation. Tell how many solutions each equation has and whether the solutions are real or imaginary.

x^2 - 4x - 5 = 0

+1
Answers (2)
  1. 25 November, 01:05
    0
    Answer:Either - 1 or, 5

    Step-by-step explanation:

    x²-4x-5=0

    x²-5x+x-5=0

    (x+1) (x-5) = 0

    Either x=-1 or, x=5
  2. 25 November, 02:34
    0
    Answer: Discriminant is 36. There are two real solutions (both different)

    Explanation:

    The equation 1x^2 - 4x - 5 = 0 is in the form ax^2 + bx + c = 0. We see that

    a = 1, b = - 4, c = - 5

    So the discriminant is

    D = b^2 - 4ac

    D = (-4) ^2 - 4 (1) (-5)

    D = 16 + 20

    D = 36 is the discriminant

    The discriminant is positive, so there are two different solutions. The solutions are both real.

    note: because the discriminant is a perfect square, this means that the two solutions are rational (ie fractions of whole numbers).
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