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14 December, 00:15

After t seconds, a ball tossed in the air from the ground level reaches a height of h feet given by the equation h = 144t-16t^2. After how many seconds will the ball hit the ground before rebounding?

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Answers (2)
  1. 14 December, 01:53
    0
    9 seconds.

    Step-by-step explanation:

    When the ball hits the ground before rebounding its height = 0, so:

    144t - 16t^2 = 0

    -16t (t - 9) = 0

    t = 0, 9 seconds.

    t = 0 corresponds to the times when it was first thrown. T = 9 seconds is the answer.
  2. 14 December, 03:45
    0
    h (t) = 144·t - 16·t^2 = 16·t· (9 - t) = 0

    9 - t = 0 - -> t = 9

    The ball will hit the ground after 9 seconds.
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