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2 October, 01:24

Given a circle with center at (10,9) and a radius of 3 what is the equation of a circle

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  1. 2 October, 03:39
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    solution given that

    (h k) = (10 9)

    r=3

    then we know that

    equatiin of circle with radius 3 unit and centre at (10 9) is

    (x-h) ^2 + (y-k) ^2=r^2

    (x-10) ^2 + (y-9) ^2=3^2

    x^2-2*x*10+10^2+y^2-2*y*9+9^2=9

    x^2-20x+100+y^2-18y+81=9

    x^2+y^2-20x-18y+180=0ans
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