Ask Question
29 April, 23:35

Assume that an int variable x that has already been declared, and initialized to a non-negative value. write an expression whose value is the last (rightmost) digit of x.

+5
Answers (2)
  1. 30 April, 00:07
    0
    x % 10

    Step-by-step explanation:

    Given that an int variable x has been declared and initialized to a non-negative value. In order to determine the last digit of x, we need to find the remainder of x when divided by 10. In programming languages such an operation is represented using the modulus (%) operator. So the required expression is given by x%10.

    For example, if x = 29, then x%10 will be 9, that is remainder of 29 when divided by 10.
  2. 30 April, 00:23
    0
    We know that an int variable, x, has been declared

    It has been assigned a non-negative value

    We need to write an expression that extracts the rightmost digit of x

    The logic for doing so would be to divide the number by 10, and checking the remainder. The remainder will always yield the rightmost digit. In case the number is a multiple of 10 then the remainder would be 0 (which would be the rightmost digit of the number)

    So we can do so by:

    int y = x % 10;

    % is the modulo function, which returns the remainder after carrying out division

    we have declared y to be int, as % will always return int values.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Assume that an int variable x that has already been declared, and initialized to a non-negative value. write an expression whose value is ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers