If n (U) = 360, n (A) = 240, n (B) = 160, find the maximum value of

n (AUB) and the minimum value of n (A n B). When will the value of

n (An B) be maximum and find its value.

here is answer

Step-by-step explanation:

n (AUB) = n (A) + n (B) - n (AnB)

= 240 + 160 - n (A n B)

= 400 - n (AnB)

Since n (AnB) 20, so n (AUB) S 400

But n (U) = 360, so n (A U B) * 360

... the maximum value of n (AUB) = 360.

When n (A U B) is maximum, n (AnB) will be minimum.

... min. value of n (An B)

= n (A) + n (B) - Max, value of n (AUB)

= 240 - 160 - 360 = 40

Again, n (

A B) will be maximum when B C A.

... the max. value of n (

A B) = n (B) = 160