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8 March, 18:03

The value of k so that the sequence k-1, k+3, 3k-1 forms an arithmetic progression is?

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  1. 8 March, 21:32
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    k = 4.

    Step-by-step explanation:

    An arithmetic sequence has a common difference.

    So for this to be arithmetic:

    k + 3 - (k - 1) = 3k - 1 - (k + 3)

    k + 3 - k + 1 = 3k - 1 - k - 3

    3 + 1 = 2k - 4

    4 + 4 = 2k

    k = 4.

    The sequence is 3, 7, 11.
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