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11 December, 10:25

Find the sum of the first 44 terms of the following series, to the nearest integer. 10, 14,18, ...

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  1. 11 December, 13:54
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    4224

    Step-by-step explanation:

    Here, we want to calculate the sum of the first 44 digits

    Term a which is first digit is 10

    common difference which is difference of terms = 14-10 = 18-14 = 4

    Now the nth term of an arithmetic sequence is

    a + (n-1) d

    44th term means n = 44

    10 + (44-1) 4

    10 + 43 (4)

    10 + 172 = 182

    To find the sum, we use the formula

    Sn = n/2[a + L]

    where a is the first term and L is the 44th term

    Sn = 44/2 (10 + 182)

    Sn = 22 (192)

    Sn = 4,224
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