Find the vertex of the parabol whose equatio is y = 3x^2+6x+1

(-1,-2)

Step-by-step explanation:

y=ax^2+bx+c

Find - b / (2a) and you will have found the x-coordinate of the vertex of this parabola.

You can find the y-coordinate that corresponds to it by plugging in your into the original equation.

-b / (2a) = -6 / (2*3) = -6/6=-1

Now replace x with - 1

3 (-1) ^2+6 (-1) + 1

3-6+1

-3+1

-2

So the vertex is (-1,-2)