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Mathematics
Salazar
12 November, 20:00
What are the zeroes of f (x) = y2 - 2x - 3?
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Layne Key
12 November, 20:08
0
Step-by-step explanation:
Product = - 3
Sum = - 2
Factors = - 3, 1
y² - 2y - 3 = y² + y - 3y - 3
= y (y + 1) - 3 (y + 1)
= (y + 1) (y - 3)
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Kamari Wade
12 November, 22:46
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x=y^2/2 - 3/2
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