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17 August, 05:20

20sin^4 x power reduction

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Answers (1)
  1. 17 August, 07:51
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    Step-by-step explanation:

    20 sin^4x

    =5 (4sin^4 x)

    =5 (2sin²x) ²

    =5 (1-cos 2x) ²

    =5 (1-4cos2x+cos² (2x))

    =5[1-4cos (2x) + {1+cos (4x) }/2]

    =5/2[2-8cos (2x) + 1+cos (4x) ]

    =5/2[3-8cos (2x) + cos (4x) ]
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