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Zion Gould
17 August, 05:20
20sin^4 x power reduction
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Franky
17 August, 07:51
0
Step-by-step explanation:
20 sin^4x
=5 (4sin^4 x)
=5 (2sin²x) ²
=5 (1-cos 2x) ²
=5 (1-4cos2x+cos² (2x))
=5[1-4cos (2x) + {1+cos (4x) }/2]
=5/2[2-8cos (2x) + 1+cos (4x) ]
=5/2[3-8cos (2x) + cos (4x) ]
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