1 substitute p=5, q=7, r = - 2

a) 2q + 5r

b) 3 (p+6) + q + r

c) 3m (8 + n) + n squared (basicly n x n)

2 substitute m=2, n = 3, p = - 5

a) m (3m+4n)

b) n squared (m+p sqaured)

c) 3m (8+n) + n sqaured

1.

a.) 2q + 5r

2 (7) + 5 (-2)

14 - 10 = 4

b.) 3 (p + 6) + q + r Plug in the numbers

3 (5 + 6) + 7 - 2 Solve inside the parentheses first

3 (11) + 7 - 2

33 + 5 = 38

2.

a.) m (3m + 4n)

2 (3 (2) + 4 (3))

2 (6 + 12)

2 (18) = 36

b.) n² (m + p²)

(3) ² (2 + (-5) ²)

9 (2 + 25)

9 (27) = 243

c.) 3m (8 + n) + n²

3 (2) (8 + 3) + 3²

6 (11) + 9

66 + 9 = 75