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30 September, 16:15

Douglas Stationery sells cards in packs of 6 and envelopes in packs of 8. If Jesse wants the same number of each, what is the minimum number of cards that he will have to buy?

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Answers (2)
  1. 30 September, 17:10
    0
    4 packs of card, totaling 24 cards

    Step-by-step explanation:

    Given that the stationery sells the cards and envelopes in packs of 6 and 8 respectively, to get the same number of each, he must buy each item to be equivalent to the lowest common multiple of the two numbers.

    The lowest common multiple of 6 and 8 is 24. As such if he buys 24 of each, he would have bought a number of cards equivalent to

    = 24/6

    = 4 packs
  2. 30 September, 18:28
    0
    The minimum number of cards that Jesse will have to buy is 24.

    Step-by-step explanation:

    We are given that Douglas Stationery sells;

    cards in packs of 6

    envelopes in packs of 8

    We want to find the minimum number of cards If Jesse wants the same number of each.

    This can be found by taking the least common multiple (LCM) of the pack of cards and pack of envelops.

    LCM by division:

    | 6, 8

    2 | 3, 4

    2 | 3, 2

    2 | 3, 1

    3 | 1, 1

    So the LCM is

    LCM = 2*2*2*3

    LCM = 24
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