A baseball is thrown upward and its height after t seconds can be described by formula h (t) = -16t2+50t+5. Find the maximum height the ball will reach.

h (t) = - 16t² + 50t + 5

The maximum height is the y vertex of this parabola.

Vertex = (-b/2a, - Δ/4a)

The y vertex is - Δ/4a

So,

The maxium height is - Δ/4a

Δ = b² - 4. a. c

Δ = 50² - 4. (-16).5

Δ = 2500 + 320

Δ = 2820

H = - 2820/4. (-16)

H = - 2820/-64

H = 2820/64

H = 44.0625

So, the maxium height the ball will reach is 44.0625