Four times the first of three consecutive even integers is six more than the product of two and the third integer. Find the integers.

The solution to this problem is as follows:

1. Assign your variables.

Let X = first integer

X+2 = second integer

X+4 = third integer

*note: multiples of 2 are added because the problem states that they are consecutive even integers.

2. Formulate the equation

4X = 6 + 2 (X+4)

X=7

3. Solve other variables

first integer = 7

second integer = 7+2 = 9

third integer = 7+4 = 11

As you can see, the answers are all odd which means that the given information in the problem should say odd, not even.