Ask Question
23 March, 07:44

Divide the Polynomials

(6a³ + 14a² - 11a - 5) : (3a + 1) =

6t³ - t² - 3t + 2 : 2t - 1 =

(4y³ - 7y + 3) : (2y + 3) =

+1
Answers (1)
  1. 23 March, 09:13
    0
    1. 2a^2+4a-5

    2. 6t^3-t^2-2t-1

    3. 2y^2-3y+1
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Divide the Polynomials (6a³ + 14a² - 11a - 5) : (3a + 1) = 6t³ - t² - 3t + 2 : 2t - 1 = (4y³ - 7y + 3) : (2y + 3) = ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers