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18 June, 03:35

What is the range of the function y = 2e x-1

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  1. 18 June, 04:15
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    The range of y = ex is all numbers greater than 0, so since the function has been shifted up 1, the new range of the function is all numbers greater than 1. Since the argument of any log must be greater than 0, (x-1) / 2 > 0. Thus x - 1 > 0, so x > 1
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